Given a fair six-faced dice where the faces are labelled $'1'$, $'2'$, $'3'$, $'4'$, $'5'$, and $'6'$, what is the probability of getting a $'1'$ on the first roll of the dice and a $'4'$ on the second roll?
- $\frac{1}{36}$
- $\frac{1}{6}$
- $\frac{5}{6}$
- $\frac{1}{3}$