edited by
0 0 votes

The following table and figure (not to scale) show characteristics of a catchment

$$\begin{array}{|c|c|c|c|} \hline \text{Sub-} & \text{Area}  &\text{Runoff} & \text{Time of} \\
\text{catchment} 
& (ha)  & \text{coefficient}  &
  \text{concentration} \\
\hline \boldsymbol{P} & 750 & 0.5 & 1 \text{ hour} \\
\hline \boldsymbol{Q} & 1000 & 0.6 & 2 \text { hour} \\
\hline \boldsymbol{R} & 1500 & 0.6 & 3 \text{ hour} \\
\hline \boldsymbol{S} & 2000 & 0.7 & 4 \text{ hour} \\
\hline
\end{array}$$



The hyetograph resulting from a storm that occurred uniformly over the catchment, is as follows


Assuming a constant base flow of $40 \mathrm{~m}^{3} / \mathrm{s}$, the peak of the runoff hydrograph produced by storm for the catchment at the outlet $\boldsymbol{O}$ is $\_\_\_\_\_ \: \mathrm{m}^{3 /} \mathrm{s}$. (rounded off to two decimal places)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Answer: