0 0 votes Assuming $s>\mid a \mid$; Laplace transform of $f(x)=\cosh a x$ is $\frac{s}{s^{2}+a^{2}}$ $\frac{a}{s^{2}+a^{2}}$ $\frac{s}{s^{2}-a^{2}}$ $\frac{a}{s^{2}-a^{2}}$ Calculus gatees-2025 calculus + – Shubham Sharma 2 1.4k points answer 0 reply