0 0 votes Given $f(x)=3 x^{4}+4 x^{3}-12 x^{2}+6$, the minimum value of $f(x)$ is $\_\_\_\_$.$-6$$-36$$-26$$-46$ Calculus gatees-2026 calculus analytical-aptitude + – gatecse 1.4k points answer 0 reply